Random Forest Project

For this project we will be exploring publicly available data from LendingClub.com. Lending Club connects people who need money (borrowers) with people who have money (investors). Hopefully, as an investor you would want to invest in people who showed a profile of having a high probability of paying you back. We will try to create a model that will help predict this.

Lending club had a very interesting year in 2016, so let's check out some of their data and keep the context in mind. This data is from before they even went public.

We will use lending data from 2007-2010 and be trying to classify and predict whether or not the borrower paid back their loan in full. You can download the data from here or just use the csv already provided. It's recommended you use the csv provided as it has been cleaned of NA values.

Here are what the columns represent:

  • credit.policy: 1 if the customer meets the credit underwriting criteria of LendingClub.com, and 0 otherwise.
  • purpose: The purpose of the loan (takes values "credit_card", "debt_consolidation", "educational", "major_purchase", "small_business", and "all_other").
  • int.rate: The interest rate of the loan, as a proportion (a rate of 11% would be stored as 0.11). Borrowers judged by LendingClub.com to be more risky are assigned higher interest rates.
  • installment: The monthly installments owed by the borrower if the loan is funded.
  • log.annual.inc: The natural log of the self-reported annual income of the borrower.
  • dti: The debt-to-income ratio of the borrower (amount of debt divided by annual income).
  • fico: The FICO credit score of the borrower.
  • days.with.cr.line: The number of days the borrower has had a credit line.
  • revol.bal: The borrower's revolving balance (amount unpaid at the end of the credit card billing cycle).
  • revol.util: The borrower's revolving line utilization rate (the amount of the credit line used relative to total credit available).
  • inq.last.6mths: The borrower's number of inquiries by creditors in the last 6 months.
  • delinq.2yrs: The number of times the borrower had been 30+ days past due on a payment in the past 2 years.
  • pub.rec: The borrower's number of derogatory public records (bankruptcy filings, tax liens, or judgments).

Import Libraries

Import the usual libraries for pandas and plotting. You can import sklearn later on.

In [1]:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns
%matplotlib inline
sns.set_style("darkgrid")
In [2]:
import warnings
warnings.filterwarnings('ignore')

Get the Data

Use pandas to read loan_data.csv as a dataframe called loans.

In [3]:
loans = pd.read_csv('loan_data.csv')

Check out the info(), head(), and describe() methods on loans.

In [4]:
loans.info()

<class 'pandas.core.frame.DataFrame'>
RangeIndex: 9578 entries, 0 to 9577
Data columns (total 14 columns):
credit.policy        9578 non-null int64
purpose              9578 non-null object
int.rate             9578 non-null float64
installment          9578 non-null float64
log.annual.inc       9578 non-null float64
dti                  9578 non-null float64
fico                 9578 non-null int64
days.with.cr.line    9578 non-null float64
revol.bal            9578 non-null int64
revol.util           9578 non-null float64
inq.last.6mths       9578 non-null int64
delinq.2yrs          9578 non-null int64
pub.rec              9578 non-null int64
not.fully.paid       9578 non-null int64
dtypes: float64(6), int64(7), object(1)
memory usage: 1.0+ MB
In [5]:
loans.describe()
Out[5]:
credit.policy int.rate installment log.annual.inc dti fico days.with.cr.line revol.bal revol.util inq.last.6mths delinq.2yrs pub.rec not.fully.paid
count 9578.000000 9578.000000 9578.000000 9578.000000 9578.000000 9578.000000 9578.000000 9.578000e+03 9578.000000 9578.000000 9578.000000 9578.000000 9578.000000
mean 0.804970 0.122640 319.089413 10.932117 12.606679 710.846314 4560.767197 1.691396e+04 46.799236 1.577469 0.163708 0.062122 0.160054
std 0.396245 0.026847 207.071301 0.614813 6.883970 37.970537 2496.930377 3.375619e+04 29.014417 2.200245 0.546215 0.262126 0.366676
min 0.000000 0.060000 15.670000 7.547502 0.000000 612.000000 178.958333 0.000000e+00 0.000000 0.000000 0.000000 0.000000 0.000000
25% 1.000000 0.103900 163.770000 10.558414 7.212500 682.000000 2820.000000 3.187000e+03 22.600000 0.000000 0.000000 0.000000 0.000000
50% 1.000000 0.122100 268.950000 10.928884 12.665000 707.000000 4139.958333 8.596000e+03 46.300000 1.000000 0.000000 0.000000 0.000000
75% 1.000000 0.140700 432.762500 11.291293 17.950000 737.000000 5730.000000 1.824950e+04 70.900000 2.000000 0.000000 0.000000 0.000000
max 1.000000 0.216400 940.140000 14.528354 29.960000 827.000000 17639.958330 1.207359e+06 119.000000 33.000000 13.000000 5.000000 1.000000
In [6]:
loans.head()
Out[6]:
credit.policy purpose int.rate installment log.annual.inc dti fico days.with.cr.line revol.bal revol.util inq.last.6mths delinq.2yrs pub.rec not.fully.paid
0 1 debt_consolidation 0.1189 829.10 11.350407 19.48 737 5639.958333 28854 52.1 0 0 0 0
1 1 credit_card 0.1071 228.22 11.082143 14.29 707 2760.000000 33623 76.7 0 0 0 0
2 1 debt_consolidation 0.1357 366.86 10.373491 11.63 682 4710.000000 3511 25.6 1 0 0 0
3 1 debt_consolidation 0.1008 162.34 11.350407 8.10 712 2699.958333 33667 73.2 1 0 0 0
4 1 credit_card 0.1426 102.92 11.299732 14.97 667 4066.000000 4740 39.5 0 1 0 0

Exploratory Data Analysis

Let's do some data visualization! We'll use seaborn and pandas built-in plotting capabilities, but feel free to use whatever library you want. Don't worry about the colors matching, just worry about getting the main idea of the plot.

Create a histogram of two FICO distributions on top of each other, one for each credit.policy outcome.

Note: This is pretty tricky, feel free to reference the solutions. You'll probably need one line of code for each histogram, I also recommend just using pandas built in .hist()

In [7]:
plt.subplots(figsize = (10,6))
sns.distplot(loans[loans['credit.policy'] == 0]['fico'], bins = 35, kde = False, color = 'red', label = 'Credit Policy = 0')
sns.distplot(loans[loans['credit.policy'] == 1]['fico'], bins = 35, kde = False, color = 'blue', label = 'Credit Policy = 1')
plt.xlim(600,850)
plt.ylim(0,900)
plt.legend(loc = 1)
plt.xlabel('FICO')
Out[7]:
Text(0.5,0,'FICO')

Create a similar figure, except this time select by the not.fully.paid column.

In [8]:
plt.subplots(figsize = (10,6))
sns.distplot(loans[loans['not.fully.paid'] == 0]['fico'], bins = 35, kde = False, color = 'red', label = 'Not Fully Paid = 0')
sns.distplot(loans[loans['not.fully.paid'] == 1]['fico'], bins = 35, kde = False, color = 'blue', label = 'Not Fully Paid = 1')
plt.xlim(600,850)
plt.ylim(0,900)
plt.legend(loc = 1)
plt.xlabel('FICO')
Out[8]:
Text(0.5,0,'FICO')

Create a countplot using seaborn showing the counts of loans by purpose, with the color hue defined by not.fully.paid.

In [9]:
plt.subplots(figsize = (12,6))
sns.countplot(x = 'purpose', hue = 'not.fully.paid', data = loans)
Out[9]:
<matplotlib.axes._subplots.AxesSubplot at 0x117b176a0>

Let's see the trend between FICO score and interest rate. Recreate the following jointplot.

In [10]:
sns.jointplot(x = 'fico', y = 'int.rate', data = loans)
Out[10]:
<seaborn.axisgrid.JointGrid at 0x117cabcf8>

Create the following lmplots to see if the trend differed between not.fully.paid and credit.policy. Check the documentation for lmplot() if you can't figure out how to separate it into columns.

In [11]:
sns.lmplot(x = 'fico', y = 'int.rate', col = 'not.fully.paid', hue = 'credit.policy', data = loans)
Out[11]:
<seaborn.axisgrid.FacetGrid at 0x117f3fbe0>

Setting up the Data

Let's get ready to set up our data for our Random Forest Classification Model!

Check loans.info() again.

In [12]:
loans.info()

<class 'pandas.core.frame.DataFrame'>
RangeIndex: 9578 entries, 0 to 9577
Data columns (total 14 columns):
credit.policy        9578 non-null int64
purpose              9578 non-null object
int.rate             9578 non-null float64
installment          9578 non-null float64
log.annual.inc       9578 non-null float64
dti                  9578 non-null float64
fico                 9578 non-null int64
days.with.cr.line    9578 non-null float64
revol.bal            9578 non-null int64
revol.util           9578 non-null float64
inq.last.6mths       9578 non-null int64
delinq.2yrs          9578 non-null int64
pub.rec              9578 non-null int64
not.fully.paid       9578 non-null int64
dtypes: float64(6), int64(7), object(1)
memory usage: 1.0+ MB

Categorical Features

Notice that the purpose column as categorical

That means we need to transform them using dummy variables so sklearn will be able to understand them. Let's do this in one clean step using pd.get_dummies.

Let's show you a way of dealing with these columns that can be expanded to multiple categorical features if necessary.

Create a list of 1 element containing the string 'purpose'. Call this list cat_feats.

In [13]:
cat_feats = ['purpose']

Now use pd.get_dummies(loans,columns=cat_feats,drop_first=True) to create a fixed larger dataframe that has new feature columns with dummy variables. Set this dataframe as final_data.

In [14]:
final_data = pd.get_dummies(loans, columns = cat_feats, drop_first = True)
In [15]:
final_data.head()
Out[15]:
credit.policy int.rate installment log.annual.inc dti fico days.with.cr.line revol.bal revol.util inq.last.6mths delinq.2yrs pub.rec not.fully.paid purpose_credit_card purpose_debt_consolidation purpose_educational purpose_home_improvement purpose_major_purchase purpose_small_business
0 1 0.1189 829.10 11.350407 19.48 737 5639.958333 28854 52.1 0 0 0 0 0 1 0 0 0 0
1 1 0.1071 228.22 11.082143 14.29 707 2760.000000 33623 76.7 0 0 0 0 1 0 0 0 0 0
2 1 0.1357 366.86 10.373491 11.63 682 4710.000000 3511 25.6 1 0 0 0 0 1 0 0 0 0
3 1 0.1008 162.34 11.350407 8.10 712 2699.958333 33667 73.2 1 0 0 0 0 1 0 0 0 0
4 1 0.1426 102.92 11.299732 14.97 667 4066.000000 4740 39.5 0 1 0 0 1 0 0 0 0 0

Train Test Split

Now its time to split our data into a training set and a testing set!

Use sklearn to split your data into a training set and a testing set as we've done in the past.

In [16]:
from sklearn.model_selection import train_test_split
In [17]:
X = final_data.drop('not.fully.paid', axis = 1)
y = final_data['not.fully.paid']

X_train, X_test, y_train, y_test = train_test_split(X, y, test_size = 0.3 , random_state= 101)

Training a Decision Tree Model

Let's start by training a single decision tree first!

Import DecisionTreeClassifier

In [18]:
from sklearn.tree import DecisionTreeClassifier

Create an instance of DecisionTreeClassifier() called dtree and fit it to the training data.

In [19]:
dtree = DecisionTreeClassifier()
In [20]:
dtree.fit(X_train, y_train)
Out[20]:
DecisionTreeClassifier(class_weight=None, criterion='gini', max_depth=None,
            max_features=None, max_leaf_nodes=None,
            min_impurity_decrease=0.0, min_impurity_split=None,
            min_samples_leaf=1, min_samples_split=2,
            min_weight_fraction_leaf=0.0, presort=False, random_state=None,
            splitter='best')

Predictions and Evaluation of Decision Tree

Create predictions from the test set and create a classification report and a confusion matrix.

In [21]:
y_predict = dtree.predict(X_test)
In [22]:
from sklearn.metrics import confusion_matrix, classification_report
In [23]:
print(classification_report(y_test, y_predict))

             precision    recall  f1-score   support

          0       0.85      0.83      0.84      2431
          1       0.19      0.22      0.20       443

avg / total       0.75      0.73      0.74      2874
In [24]:
print(confusion_matrix(y_test, y_predict))

[[2006  425]
 [ 344   99]]

Training the Random Forest model

Now its time to train our model!

Create an instance of the RandomForestClassifier class and fit it to our training data from the previous step.

In [25]:
from sklearn.ensemble import RandomForestClassifier
In [26]:
rforest = RandomForestClassifier(n_estimators = 300)
In [27]:
rforest.fit(X_train, y_train)
Out[27]:
RandomForestClassifier(bootstrap=True, class_weight=None, criterion='gini',
            max_depth=None, max_features='auto', max_leaf_nodes=None,
            min_impurity_decrease=0.0, min_impurity_split=None,
            min_samples_leaf=1, min_samples_split=2,
            min_weight_fraction_leaf=0.0, n_estimators=300, n_jobs=1,
            oob_score=False, random_state=None, verbose=0,
            warm_start=False)

Predictions and Evaluation

Let's predict off the y_test values and evaluate our model.

Predict the class of not.fully.paid for the X_test data.

In [28]:
y_predict = rforest.predict(X_test)

Now create a classification report from the results. Do you get anything strange or some sort of warning?

In [29]:
print(classification_report(y_test,y_predict))

             precision    recall  f1-score   support

          0       0.85      1.00      0.92      2431
          1       0.50      0.02      0.03       443

avg / total       0.79      0.85      0.78      2874

Show the Confusion Matrix for the predictions.

In [30]:
print(confusion_matrix(y_test,y_predict))

[[2423    8]
 [ 435    8]]

What performed better the random forest or the decision tree?

Overall the Random Forest performed better than the single decision tree. However, in certain cases such as recall and f1-score for class = 1 the single decision tree performed better than the Random Forest. Therefore, the actual choice will depend on what metric the analyzer cares about the most.

Great Job!